waves - Why do we demand that $\lambda \ll \text{size of slit

I'd appreciate it if anyone could explain to me why do we demand that the wavelength will be much smaller than the distances between the slits in order to see wave diffraction when performing Young's

Solved 1. For a single slit, how must the size d of the slit

S-Parameters for Calculating the Maximum Efficiency of a MIMO-WPT System

Interference and the Two-slit Experiment

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Physics-Embedded Machine Learning for Electromagnetic Data Imaging

28th IAEA Fusion Energy Conference (FEC 2020) (10-15 May 2021) · Indico for IAEA Conferences

Lightwave electronics in condensed matter

Super Bound States in the Continuum on Photonic Flatband: Concept, Experimental Realization, and Optical Trapping Demonstration

Correlated Phases in Spin-Orbit-Coupled Rhombohedral Trilayer Graphene

28th IAEA Fusion Energy Conference (FEC 2020) (10-15 May 2021) · Indico for IAEA Conferences

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6.5 Diffraction through a single slit, 2d and 3d wavefronts

6.5 Diffraction through a single slit, 2d and 3d wavefronts